Java Program to find leap year or not

Here is a simple Java program for beginners,

Write a Java program to find a leap year or not.

Formula for finding a Leap year is as follows:

1. A year should be evenly divisible by 4 (should not have a reminder):

    year % 4 == 0 ( reminder should be 0 )

2. AND Year should not be evenly divisible by 100 (should have a reminder):

    year % 100 != 0 ( reminder should not be 0 )

3. OR Year should be evenly divisible by 400 (should have a reminder):

    year%400 == 0 ( reminder should be 0 )

So basically 1 && 2 || 3

if (1  and 2) both are true or 3 is true then it is a leap year

Here is the Java program to find the leap year,

import java.util.Scanner;

/**
 *
 * @author agur
 */
public class LeapYear {

    public static void main(String[] args) {
        int year;

        Scanner in = new Scanner(System.in);
        System.out.println("Enter a year:");
        year = in.nextInt();

        if ((0 == year % 4) && (0 != year % 100) || (0 == year % 400)) {
            System.out.println(year+" is a leap year");
        } else {
            System.out.println(year+" is not a leap year");
        }
    }
}

run:
Enter a year:
1997
1997 is not a leap year
BUILD SUCCESSFUL (total time: 3 seconds)

run:
Enter a year:
1996
1996 is a leap year
BUILD SUCCESSFUL (total time: 1 second)