C program to find the Total marks & Percentage of a Student

In this post, we are going to see how to write a C program to find Student Total marks & Percentages.

What will you learn in this C program?:

1. How to get the number of subjects dynamically.
2. You will learn how to set a dynamic array variable in C.
3. Get the size of an array in C.
4. How to find the percentage in C language.

#include <stdio.h>

int main() {
	
    //set the integers
    int subj, i, mark;
    float total = 0, percentage;

    printf("No. of Subjects?: ");
    scanf("%d", &subj);
    
    //dynamic array
    int marks[subj];
	
    //get the array size
    int arr_size = sizeof(marks) / sizeof(marks[0]);
    
    //for loop to get the marks & calculate them
    for(i=0; i < arr_size; i++) {
    	printf("Subject %d:", i+1);
    	scanf("%d", &mark);
		total = total + mark;
	}
	
	//let's find the percentage
	percentage = ( total / arr_size * 100) / 100;
	
	//print the result
    printf("Total marks = %f\n", total);    
    printf("Percentage = %f\n", percentage);
    return 0;
    
}

Output:

No. of Subjects?: 6
Subject 1:98
Subject 2:95
Subject 3:85
Subject 4:79
Subject 5:81
Subject 6:80
Total marks = 518.000000
Percentage = 86.333344

--------------------------------
Process exited after 23.24 seconds with return value 0
Press any key to continue . . .

Read the inline comments to understand each section of the program. I believe this post would have helped you to understand how to write a C program to find Student marks.